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Inverse function of f(x)=2/x^2

User Fozoglu
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1 Answer

4 votes

Explanation:

let y= f(x)= 2/x^2


{x}^(2) = (2)/(y) \\ or \: x = \sqrt{ (2)/(y) } \\

or, f-1(y) = Root(2/y)

or, f-1(x) = Root (2/x)

this is the inverse function of the given.......

User Leemour
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