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A 2.65 g sample of an unknown gas at 33 ∘ C and 1.00 atm is stored in a 2.85 L flask. What is the density of the gas?

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Answer:

δ = 9.298 E-4 g/mL

Step-by-step explanation:

assuming ideal gas:

  • PV = RTn
  • δ = m/V

∴ mass (m) = 2.65 g

∴ T = 33°C = 306 K

∴ P = 1.00 atm

∴ V = 2.85 L = 2850 mL

⇒ δ = (2.65 g)/(2850 mL)

⇒ δ = 9.298 E-4 g/mL

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