The system of linear inequalities are:
![a + b \geq 20\\\\2.50a + 7b\leq 80](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vwl29292txhe2khxebuwjzw6hs66gyi8f7.png)
Solution:
Let "a" be the number of small candles bought
Let "b" be the number of large candles bought
Cost of each small candle = $ 2.50
Cost of each large candle = $ 7
He needs to buy at least 20 candles
Therefore, number of small candles and number of large candles bought must be at least 20
Thus, we frame a inequality as:
![a + b\geq 20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xxal2bk3xehpgekrhigxyusancjz0l2f2p.png)
"at least" means greater than or equal to
Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also
He can spend no more than 80 dollars
Which means, he spend maximum 80 dollars or less than 80 dollars also
So we have to use "less than or equal to" symbol
Thus, we frame a inequality as:
Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle
80
![a * 2.50 + b * 7 \leq 80\\\\2.50a + 7b\leq 80](https://img.qammunity.org/2021/formulas/mathematics/middle-school/m73zhxgiat7lekxr1ew1keoqbhic3hycdb.png)
Thus the system of linear inequalities are:
![a + b \geq 20\\\\2.50a + 7b\leq 80](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vwl29292txhe2khxebuwjzw6hs66gyi8f7.png)