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How many moles are contained in .250 grams of N-acetyl-p-toluidine? Enter only the number to three significant figures.

User Beniaminus
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1 Answer

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Answer: The amount of N-acetyl-p-toluidine is
1.68* 10^(-3)mol

Step-by-step explanation:

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of N-acetyl-p-toluidine = 0.250 g

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

Putting values in above equation, we get:


\text{Moles of N-acetyl-p-toluidine}=(0.250g)/(149.2g/mol)=1.68* 10^(-3)mol

Hence, the amount of N-acetyl-p-toluidine is
1.68* 10^(-3)mol

User Shaharg
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