Question

You have 716.7 ml of 3.86 M HCl. Using a volumetric pipet, you take 119.56 ml of that solution and dilute it to 969.88 ml in a volumetric flask. Now you take 100.00 ml of that solution and dilute it to 145.62 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution? Enter to 4 decimal places.

Answer 1

0.327 M is the concentration of hydrochloric acid in the final solution.

Step-by-step explanation:

Case 1:

716.7 ml of 3.86 M HCl. Using a volumetric pipet, you take 119.56 ml of that solution and dilute it to 969.88 ml in a volumetric flask.

Before dilution :

`M_1=3.86 M, V_1=119.56 ml`

After dilution :

`M_2=?, V_2=969.88 ml`

`M_1V_1=M_2V_2` ( dilution )

`M_2=(M_1V_1)/(V_2)=(3.86 M* 119.56 mL)/(969.88 mL)`

`M_2=0.4758 M`

Case 2:

Now you take 100.00 ml of case 1 solution and dilute it to 145.62 ml in a volumetric flask

Before diluting it further :

`M_2=0.4758 M, V_1=100.00 ml`

After dilution :

`M_3=?, V_3=145.62 ml`

`M_3V_3=M_2V_2` ( dilution )

`M_3=(M_2V_2)/(V_3)=(0.4758 M* 100.00 mL)/(145.62 mL)`

`M_3=0.327 M`

0.327 M is the concentration of hydrochloric acid in the final solution.