Question

HELP PLEASE!

can anyone help me with this math question? im quite confused on where to begin..

please explain & show the steps!

Answer 1

Answer: -3x-2y+1

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Step-by-step explanation:

In the first parenthesis grouping, we have these three terms

`9x^2y`

`6xy^2`

`-3xy`

and we're dividing each of them over the denominator -3xy.

Think of it like the distributive property. In fact, division is a disguised version of multiplication, which is why the distributive property is not a coincidence. Example: 10/2 = 10*(1/2) = 10*0.5 = 5

If we divide each term over -3xy, then we get these three separate results:

`(9x^2y) / (-3xy) = -3x`

`(6xy^2) / (-3xy) = -2y`

`(-3xy) / (-3xy) = 1`

The last equation is probably self explanatory: any number divided by itself is 1, as long as the number isn't zero. Eg: 4/4 = 1.

The first two equations might not be obvious. For the first equation, we divide the coefficients 9 and -3 to get -3 as the final coefficient on the right hand side. Then the variable terms cancel when pairing them up. Check out the diagram below to see what I mean by this canceling. It's optional, but it might help to think of
`x^2` as
`x*x`

A similar situation happens in the second equation as well.

After doing those three division operations, we then add up the results to arrive at -3x+(-2y)+1 which is the same as -3x-2y+1