Question

A 0.250 kg mass is attached to a spring with k=18.9 N/m. At the equilibrium position, it moves 2.89 m/s. What is the amplitude of the oscillation? (Unit=m)

Answer 1

0.33 m

Step-by-step explanation:

The work is done out above.

Answer 2

The amplitude of oscillation is 0.33 m

Step-by-step explanation:

Amplitude is the measure of change in distance occurred during oscillation. As oscillation is a to and fro motion, so amplitude consists of influence of angular frequency and maximum velocity.

It is known that velocity is maximum when the spring is in equilibrium. And angular frequency of spring is determined as the square root of spring constant divided by mass.

`angular frequency=\sqrt{(spring constant)/(Mass) }`

Angular frequency =
`\sqrt{(18.9)/(0.250) }=8.69`

And amplitude is

`A=\frac{\text {velocity}}{\text {Angular frequency}}=(2.89)/(8.69)=0.33 \mathrm{m}`

Thus , the amplitude of oscillation is 0.33 m.