What volume would be occupied by 12.4 moles of helium gas at STP

asked Apr 27, 2021 8.5k views

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3 votes

Answer: 277.8 L

Explanation: Use Ideal gas law equation:

PV= nRT

At STP: P= 1atm T = 273 K

V= nRT/ P

= 12.4 moles He ( 0.08205 L.atm/mole.K) ( 273 K) / 1 atm

= 277.8 L

Rudder answered May 3, 2021

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