Question

What is the equation in standard form of the line that passes through the point 10,-3 and has a slope of 1/5

Answer 1

Answer:
`5y - x = -25`

Explanation:

The formula for calculating equation of line when a point and a slope is gives is :

`y - y_(1) = m ( x - x_(1))`

`x_(1) = 10`

`y_(1) = -3`

`m = (1)/(5)`

substituting into the formula , we have

`y - (-3) = (1)/(5)(x - 10 )`

`y + 3 = (1)/(5)(x - 10 )`

multiply through by 5 ,

`5 (y+ 3 ) = x - 10`

`5y + 15 = x - 10`

in standard from , we have

`5y - x = -10 - 15`

`5y - x = -25`