Answer:
a.1503.52 cm^3
b.
![v=5575.3cm^(3)](https://img.qammunity.org/2021/formulas/physics/college/yopibooc3irqhgt2bz4vq9e50zkb4dn6mc.png)
c. 156.67cm
d. 5059.07m
e.
![1.50*10^(4)](https://img.qammunity.org/2021/formulas/physics/college/t2borrp0sv4m4d65lhc8k3eo9eqvu3fapj.png)
f.5.42
Step-by-step explanation:
a. from the formula used to determine the volume of a cylinder which is expressed as
![v=\pi r^(2)h](https://img.qammunity.org/2021/formulas/physics/college/zvx2gxotoxiev2sff9m5ywd1yk4lzf2lk2.png)
where r is the radius. note radius= diameter/2
and h is the height
for a cylinder of 10.2cm diameter, the radius is 10.2/2=5.2cm
and the height 18.4cm
![v =\pi *5.1^(2)*18.4\\ v =1503.52cm^(3)](https://img.qammunity.org/2021/formulas/physics/college/ga24d0y1g278qt63yclk37atpfoepgokh1.png)
b. from the formula used to determine the volume of a cylinder which is expressed as
![v =(4)/(3) \pi r^(3) \\v=(4)/(3) \pi *11^(3) \\v=5575.3cm^(3)](https://img.qammunity.org/2021/formulas/physics/college/fjh3qhp3l2nj95w951y395f2nsp3jcz8xh.png)
c. since 1ft=30.48cm
hence 5.14ft will be
5.14*30.48= 156.6672cm
d. since 1mile=1609.34m
hence 3.14356mile will be
3.14356*1609.34=5059.069425m
e. to express 15000 to 3 significant figure we have
![1.50*10^(4)](https://img.qammunity.org/2021/formulas/physics/college/t2borrp0sv4m4d65lhc8k3eo9eqvu3fapj.png)
f. the distance between two points is expressed as
![d=\sqrt{(x_(2)-x_(1))^(2) +(y_(2)-y_(1))^(2)}](https://img.qammunity.org/2021/formulas/physics/college/uwbgj9uyseg9sp85686oqzm2z014i6wlsk.png)
hence for points (1.8,3.0) and (4.5, -1.7) we have
![d=\sqrt{(4.5-1.8)^(2) +(-1.7-3.0)^(2)} \\d=√(7.29+22.09)\\ d=5.42](https://img.qammunity.org/2021/formulas/physics/college/69wh9v007m265q8ajkxz9uk722huhqf7g9.png)