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A capacitor consists of two parallel plates, each with an area of 16.0 cm2 , separated by a distance of 0.150 cm . The material that fills the volume between the plates has a dielectric constant of 6.00. The plates of the capacitor are connected to a 400 V battery.

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Answer:

Step-by-step explanation:

Given

area of capacitor
A=16\ cm^2

Distance between Capacitor
d=0.15\ cm

dielectric constant
k=6

Voltage applied
V=400\ V

Capacitance C is given by
C=k(\epsilon A)/(d)


C=6* (8.85* 10^(-12)* 16* 10^(-4))/(0.15* 10^(-2))


C=56.64* 10^(-12)\ F

Charge on Plates


Q=C* V


Q=56.64* 10^(-12)* 400


Q=22,656* 10^(-12)


Q=22.656\ nC

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