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Turnerâs treadmill runs with a velocity of â1.2 m/s and speeds up at regular intervals during a half-hour workout. After 25 min, the treadmill has a velocity of â6.5 m/s. What is the average acceleration of the treadmill during this period?

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Answer:

a=0.0035 m/s²

Step-by-step explanation:

Given that

Initial velocity ,u = 1.2 m/s

Time ,t= 25 min

We know that 1 hr= 60 min = 3600 s

t= 25 x 60 = 1500 s

The final speed ,v= 6.5 m/s

The average acceleration = a

We know v = u +at

6.5 = 1.2 + a x 1500


a=(6.5-1.2)/(1500)\ m/s^2

a=0.0035 m/s²

Therefore the acceleration will be 0.0035 m/s².

User Amer Sawan
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