Question

Convert the given amount as noted.

1.51 times 10^24 formula units of Iron (II) hydroxide to grams

Answer 1

Answer: 225.75g

Step-by-step explanation:

Molar Mass of Fe(OH)2 = 56 + 2(16 + 1) = 56 + 2(17) = 56 + 34 = 90g/mol

1mole(90g) of Fe(OH)2 contained 6.02x10^23 units.

Therefore, Xg of Fe(OH)2 will contain 1.51x10^24 units

Xg of Fe(OH)2 = (90x1.51x10^24)/6.02x10^23 = 225.75g