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A purse at radius 2.30 m and a wallet at radius 3.45 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the purse is . At that instant and in unit-vector notation, what is the acceleration of the wallet?

User Lece
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1 Answer

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Answer:

The acceleration of the wallet is
3\hat{i}+6\hat{j}

Step-by-step explanation:

Given that,

Radius of purse r= 2.30 m

Radius of wallet r'= 3.45 m

Acceleration of the purse
a=2\hat{i}+4.00\hat{j}

We need to calculate the acceleration of the wallet

Using formula of acceleration


a=r\omega^2

Both the purse and wallet have same angular velocity


\omega=\omega'


\sqrt{(a)/(r)}=\sqrt{(a')/(r')}


(a)/(r)=(a')/(r')


(a')/(a)=(r')/(r)


(a')/(a)=(3.45)/(2.30)


(a')/(a)=(3)/(2)


a'=(3)/(2)*(2\hat{i}+4.00\hat{j})


a'=3\hat{i}+6\hat{j}

Hence, The acceleration of the wallet is
3\hat{i}+6\hat{j}

User Bmorenate
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