Question

the perimeter of a rectangle is 152 meters. the width is 22 meters less than the length. find the length and width ​

Answer 1

width = 27m

length = 49m

Explanation:

we can write 2 different equations from the information given:

`1) \: \: \: \: 2l + 2w = 152 \\2) \: \: \: \: l = w + 22`

where l is length and w is width

we can then substitute equation 2 into equation 1:

`2(w + 22) + 2w = 152 \\ 4w + 44 = 152 \\ 4w = 108 \\ w = 27`

then sub w = 27 into the second equation: