101k views
3 votes
What quantity of 78% chlorine solution must be mixed with a 23% chlorine solution to produce 477.16 mL of 60% solution?

1 Answer

3 votes

Answer:

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

Explanation:

Let

x ----> quantity of 78% chlorine solution in milliliters

y ----> quantity of 23% chlorine solution in milliliters

we know that

The quantity x of 78% chlorine solution mixed with a quantity y of 23% chlorine solution produce 477.16 mL of 60% solution


78\%=78/100=0.78\\23\%=23/100=0.23\\60\%=60/100=0.60

so


x+y=477.16 ----> equation A


0.78x+0.23y=0.60(477.16)


0.78x+0.23y=286.296 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (321, 156.16)

therefore

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

What quantity of 78% chlorine solution must be mixed with a 23% chlorine solution-example-1
User Psyklopz
by
7.1k points