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From the top of a 100-ft building a man

observes a car moving toward him. If the angle of depression
of the car changes from 15° to 33° during the period of observation,
how far does the car travel?

User Hemanik
by
8.2k points

1 Answer

4 votes

Answer:

219m

Explanation:

Since the man observes the car with angle 15 before observing in 33 degrees.

For the first observation

The angle observation gives an angle if 33 degrees with the horizontal.

It gives a triangle which I'll attach to the que,

from the first triangle

Tan 33 = 100/y

Y= 100/ tan 33

Y = 153.99m.

This is the distance from the building to the distance where it was secondly observed( 33).

To find x

tan 15 = 100/(153.99+x)

153.99 + x = 100/ tan 15

153.99 + x = 373.21

The distance between the two observed angles

X= 219m.

From the top of a 100-ft building a man observes a car moving toward him. If the angle-example-1
User Jeff Fol
by
7.9k points