Question

When one gram of liquid ethanol, C2H5OH(l), is burned, 29.7 kJ of heat are released. How much heat is released when 4.337 pounds of liquid ethanol are burned?

Answer 1

When 4.337 pounds of liquid ethanol are burned, approximately 58,498.653 kJ of heat are released. To calculate this, we convert the mass from pounds to grams and then use a proportion to find the heat released.

Step-by-step explanation:

To calculate the heat released when 4.337 pounds (1970.49 grams) of liquid ethanol are burned, we can use the information that 29.7 kJ of heat is released when 1 gram of ethanol is burned. First, we need to convert the mass from pounds to grams by multiplying it by the conversion factor of 453.592 grams per pound. So, the mass of the ethanol is 1970.49 grams.

Now, we can use a proportion to calculate the heat released. We know that 1 gram of ethanol releases 29.7 kJ of heat. Let x represent the heat released when 1970.49 grams are burned:

1 g / 29.7 kJ = 1970.49 g / x

Solving for x:

x = (1970.49 g * 29.7 kJ) / 1 g = 58498.653 kJ

Therefore, when 4.337 pounds of liquid ethanol are burned, approximately 58,498.653 kJ of heat are released.

Answer 2

58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.

Step-by-step explanation:

Given that:-

When 1 gram of liquid ethanol is burnt, 29.7 kJ of energy is released.

The conversion of pounds to gram is shown below as:-

1 pound = 453.6 gram

Given mass of liquid ethanol = 4.337 pounds.

So,

4.337 pounds = 453.6*4.337 grams = 1967.2 grams

Thus,

When 1967.2 gram of liquid ethanol is burnt, 29.7*1967.2 kJ of energy is released.

58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.