Question

What is the mass of 2.23 times 10^23 atoms of sulfur

Answer 1

The atomic mass of sulfur is 32.07 g/mole.

1 mole of sulfur contains 6.022 ×10^23 atoms
But 1 mole is equal to 32.07 g
Therefore;
6.022 ×10^23 atoms = 32.07
Thus; 2.23 × 10^23 atoms = ?
= (2.23 ×10^23 ×32.07)/ 6.022×10^23
= 11.876 g