Answer:
1.32.225 N/C, direction is away from the point charge
2. 8.972*10^-12 C
3. the field is directed away from the axon
Step-by-step explanation:
The electric field can be calculated as shown below:
E = k*|q|/r^2
Where:
E = electric field; k = 8.98755*10^9 N*m^2/C^2; r = distance between the measured field and point charge = 0.05 m; q = the point charge
For 0.100 m of the axon, the value of q is:
q = (5.6*10^11)*(+e)*(0.001)
+e = charge of an electron = 1.60217*10^-19 C
Thus:
q = (5.6*10^11)*(1.60217*10^-19)*(0.0001) = 8.972*10^-12 C
Therefore:
E = (8.98755*10^9)*(8.972*10^-12)/0.05^2 = 32.255 N/C
A positive point charge always produce an electric field that is directed away from the field while a negative point charge produces an electric field that is directed toward the field