Question

Find the values of x for which the denominator is equal to zero for 2x^2+5/x^2-2x .

x = 0, x = 2

x = 1, x = 2

none

x = 2

Answer 1

꧁⫷ᴀɴsᴡᴇʀ⫸꧂

`\sf {x^2 - 2x = 0}`

`\sf {x ( x - 2) = 0}`

`\sf {x = 0 \: or \: x-2 = 0}`

`\sf \green{ {x = 0 \: or \: x = 2}}`

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Answer 2

Let's see

`\\ \rm\rightarrowtail x^2-2x=0`

`\\ \rm\rightarrowtail x(x-2)=0`

`\\ \rm\rightarrowtail x=0\:or\:x-2=0`

`\\ \rm\rightarrowtail x=0\:or\:x=2`