Question

From his base camp at the equator, Bruce hiked on flat terrain $13$ kilometers due north, then $24$ km due east, and finally $6$ km due south. Using a direct route, how many kilometers would Bruce be from base camp?

Answer 1

using Pythagoras theorem we have

`x^(2) =24^(2)+7^(2)\\x^(2) =144+49\\x^(2) =193\\x=\sqrt[]{193} \\x=13.89km`

Explanation:

step 1 : draw the diagram based on the question.

you draw a line upward 13km and draw another one to the right 24km then draw another one down 6km, now you join the the last line to the original starting point.

Step 2: after drawing the diagram above you should draw a doted line from the end of the last line due south to bisect the first line due north and label the line 24km also since it forms a rectangle.

step 3: it now forms a right-angled triangle at the bottom then you apply the Pythagoras theorem