Question

A motorcycle has a constant speed of 30.0 m/s as it passes over the top of a hill whose radius of curvature is 120 m. The mass of the motorcycle and driver is 324 kg. Find the magnitudes of the following.

Answer 1

Answer with Explanation:

We are given that

Speed of motorcycle=30 m/s

Radius of curvature=r=120 m

Mass of motorcycle=m=324 kg

a.We have to find the centripetal force .

Centripetal force=
`F_c=(mv^2)/(r)`

Substitute the values then we get

`F_c=(324* (30)^2)/(120)=2430 N`

Hence, the magnitude of centripetal force=F=2430 N

b.We have to find the normal force act on the motorcycle.

`F_c=mg-N`

Because net force is equal to centripetal force which act in downward direction.

`2430=324* 9.8-N`

Using
`g=9.8 m/s^2`

`N=324* 9.8-2430=3175.2-2430=745.2 N`

Hence, the normal force act on the motorcycle=745.2 N