Answer:
Explanation:
8-(x-2)=2x+(10-3x)
We move all terms to the left:
8-(x-2)-(2x+(10-3x))=0
We add all the numbers together, and all the variables
-(x-2)-(2x+(-3x+10))+8=0
We get rid of parentheses
-x-(2x+(-3x+10))+2+8=0
We calculate terms in parentheses: -(2x+(-3x+10)), so:
2x+(-3x+10)
We get rid of parentheses
2x-3x+10
We add all the numbers together, and all the variables
-1x+10
Back to the equation:
-(-1x+10)
We add all the numbers together, and all the variables
-1x-(-1x+10)+10=0
We get rid of parentheses
-1x+1x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0