Answer:
17.66 kPa
Step-by-step explanation:
The volume of water in the swimming pool is the product of its dimensions
V = 30 * 8.7 * 1.8 = 469.8 cubic meters
Let water density
, and g = 9.81 m/s2 we can calculate the total weight of water in the swimming pool
![W = mg = \rho V g = 1000 * 469.8 * 9.81 = 4608738 N](https://img.qammunity.org/2021/formulas/physics/college/b8t2d8uqu8b47fcxqys0u7u1rxobvtrfgq.png)
The area of the bottom
A = 30 * 8.7 = 261 square meters
Therefore the pressure is its force over unit area
or 17.66 kPa