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If the dry-bulb temperature is 93°F and the wet-bulb temperature is 60°F, what is the specific volume of the air?
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If the dry-bulb temperature is 93°F and the wet-bulb temperature is 60°F, what is the specific volume of the air?

User Lars Holdaas
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Answer:

specific volume of air= V/M

therefore= 90F/60F=1.55kg/m3.

Where V=volume of dry-bulb

and M =mass of wet bulb

Step-by-step explanation:

The Unit for volume of air is kilogram per meter cube

User Kkemple
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