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An object with a heat capacity of 345J∘C experiences a temperature change from 88.0∘C to 45.0∘C. How much heat is released in this process, in joules?

User Ulilicht
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Answer:

14835 J

Step-by-step explanation:

Recall that heat capacity, C, is the ratio of heat to the change in temperature.

C= q/ΔT

Rewrite the equation to solve for q.

q=CΔT

In order to solve for q, you must first calculate ΔT.

ΔT=Tfinal−Tinitial

ΔT=45.0∘C–88.0∘C=−43.0∘C

Next, Substitute the known values into the equation above and solve for q.

q=(345J∘C)(−43.0∘C)= −14,835 J

Round your answer to the nearest hundred to use correct significant figures.

q= −14,800 J

The negative sign means that heat is released, or the process is exothermic. Therefore, the amount of heat released is about 14,800 J.

Hope this helped!

User ItsGeorge
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