Answer:
Option b) 0.161
Explanation:
We are given the following information:
We treat correct as a success.
P(Correct Answer) =
= 0.2
Then the number of questions follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 11
We have to evaluate:
P(answer at least 4 questions correctly)

Thus, 0.161 is the probability that Richard will answer at least 4 questions correctly.
Option b) 0.161