Question

Find the number of moles of CO2− 3 produced when 0.207 mol of sodium carbonate dissolved. Answer in units of mol.

Answer 1

Answer : The number of moles of carbonate ion,
`(CO_3^(2-))` produced are, 0.207 moles.

Explanation : Given,

Moles of sodium carbonate = 0.207 mol

As we know that when sodium carbonate dissolved in water then it dissociates to give 2 sodium ion and 1 carbonate ion.

The balanced chemical reaction will be:

`Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^(2-)(aq)`

From the balanced chemical reaction we conclude that,

As, 1 mole of sodium carbonate dissociate to give 1 moles of carbonate ion,
`(CO_3^(2-))`

So, 0.207 mole of sodium carbonate dissociate to give 0.207 moles of carbonate ion,
`(CO_3^(2-))`

Thus, the number of moles of carbonate ion,
`(CO_3^(2-))` produced are, 0.207 moles.