Question

Solving the right triangle (round to the nearest tenth)

Answer 1

idk

Explanation:

idk sorry wish i could help u

Answer 2

see explanation

Explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 43)° = 180° - 133° = 47°

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tan43° =
`(opposite)/(adjacent)` =
`(23)/(b)`

Multiply both sides by b

b × tan43° = 23 ( divide both sides by tan43° )

b =
`(23)/(tan43)` ≈ 24.7 ( to the nearest tenth )

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sin43° =
`(opposite)/(hypotenuse)` =
`(23)/(c)`

Multiply both sides by c

c × sin43° = 23 ( divide both sides by sin43° )

c =
`(23)/(sin43)` ≈ 33.7 ( to the nearest tenth )