Answer:
- Second option: the graph approaches 0 as x approaches infinity.
Step-by-step explanation:
The function f(x) is:
![f(x)=(2x)/(1-x^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ngxzh81mgvbvpsrjzqdq42era3ha6cm7p1.png)
- When x approach infinity the term x² grows rapidly (more rapid than x), thus 1 - x², which is in the denominator will decrease, become a large negative more rapid than the x in the numerator. Thus you can expect that the function approaches zero.
To prove that in a more analytical way, divide both numerator and denominator by x and simplifiy:
![\lim_(x \to \infty) (2x)/(1-x^2)\\\\ \lim_(x \to \infty) (2x/x)/((1-x^2)/x)\\\\ \lim_(x \to \infty) (2)/(1/x-x)\\\\\lim_(x \to \infty) (2)/(0-x)\\ \\ \lim_(x \to \infty) (2)/(-x)\\ \\ \lim_(x \to \infty) -(2)/(x)=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qm2w4c9wy5s75uw4gpoh5nt0qs2lyj98vo.png)