Question

a circuit contains 2 ohm and 4 ohm resistors connected in parallel, find the total resistance & the amount of current in each resistor if it was connected to a 12 v battery

Answer 1

The total resistance of the circuit is 4/3 ohms. The current in the 2 ohm resistor is 6 A and the current in the 4 ohm resistor is 3 A.

Step-by-step explanation:

To find the total resistance of the circuit, we can use the formula for the equivalent resistance of resistors in parallel:

Req = 1 / (1/R1 + 1/R2)

For this circuit with 2 ohm and 4 ohm resistors in parallel, the total resistance would be:

Req = 1 / (1/2 + 1/4) = 4/3 ohms

To find the amount of current in each resistor, we can use Ohm's Law, which states that the current through a resistor is equal to the voltage across it divided by its resistance:

I = V / R

Since the circuit is connected to a 12 V battery, the current in the 2 ohm resistor would be:

I1 = 12 V / 2 ohms = 6 A

And the current in the 4 ohm resistor would be:

I2 = 12 V / 4 ohms = 3 A

Answer 2

Step-by-step explanation:

Resistance

R = R1 * R2 / (R1 + R2)

R1 = 2

R2 = 4

R = 2*4 / (2 + 4)

R = 8 / 6

R = 1.3333

Current R1

R1 = 2 ohms

V = 12 volts

I = ?

V = I * R

12 = I * 2

12/2 = I

I = 6 amperes.

Current R2

V = 12 volts

R = 4 ohms

I = ?

V = I * R

12 = I * 4

12/4 = I

I = 3 amps