Question:
Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.
what fraction of the banana did juan and raj put on their cereal altogether?
a. 2/35 banana
b. 3/12 banana
c. 3/7 banana
d. 19/35 banana
Answer:
Juan and Raj altogether put 19/35 banana
Solution:
Given that, Juan and Raj cut up a banana to put on cereal
![fraction\ of\ banana\ put\ by\ Juan = (1)/(7)\\\\fraction\ of\ banana\ put\ by\ Raj = (2)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/83a1z3kdd96g6ih7dw294nc0z11fi5yczq.png)
We have to find the fraction of banana put by Juan and Raj altogether
This means, we have to add both the fractions
![fraction\ of\ banana\ put\ altogether = fraction\ of\ banana\ put\ by\ Juan + fraction\ of\ banana\ put\ by\ Raj](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jrhjsmhodakl95sa0vol84b3izpm5dy5cd.png)
![fraction\ of\ banana\ put\ altogether = (1)/(7) + (2)/(5)\\\\\text{Cross multiply to simplify }\\\\fraction\ of\ banana\ put\ altogether = (1 * 5 + 2 * 7)/(7 * 5)\\\\fraction\ of\ banana\ put\ altogether = (5+14)/(35)\\\\fraction\ of\ banana\ put\ altogether = (19)/(35)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4886ph1y3mxbmvunsn2065z993limxxh2i.png)
Thus they put
of banana by Juan and Raj altogether