Question

Please help me ! Reduced to lowest terms

Answer 1

Explanation:

7) 2ab + 4ac = 2*a*b + 2 *2 *a*c

= 2a(b + 2c)

`(2ab^(2)c)/(2ab+4ac)=(2*a* b^(2)*c)/(2a(b+2c))\\\\\\\text{2a in the denominator and numerator get cancelled}\\\\ = (b^(2)c)/(b+2c)`

8) ac - a²c² = c( a - a²c)

bc - abc = c(b - ab)

`(ac - a^(2)c^(2))/(bc-abc^(2))=(c(a-a^(2)c))/(c(b-ab))\\\\`

`=(a-a^(2)c)/(b-abc)`

9) b²+ 4b - 5 = b² + 5b - 1b - 5

= b(b + 5) - 1(b + 5)

= (b +5)(b - 1)

b² + 8b + 15 = b² + 5b + 3b + 15

= b(b + 5) + 3(b + 5)

= (b + 5 )(b + 3)

`(b^(2)+4b-5)/(b^(2)+8b+15)=((b+5)(b-1))/((b+5)(b+3))\\\\\\`

`=(b-1)/(b+3)`