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If the kinetic energy possessed by a man of 50kg is 625J , the speed of man is

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Answer: v= 5 m/s

Explanation: Solution:

KE= 1/2 mv²

Derive to find v.

v = √ 2KE / m

Substitute the values

v = √2x 625 J / 50 kg

= √ 1250 J / 50 kg

= √ 25 kg. m/s /kg

= 5 m/s

Unit for J can be expressed in kg.m/s so we cancel kg and the remaining unit is m/s.

User Ahmed Shamel
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