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Really really appreciate some help

Really really appreciate some help-example-1
User Dan Barowy
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1 Answer

3 votes

Answer:

see below

Explanation:

We can't help you with using your tools, but we can show you what the solution will look like when you're finished.

If you need to find points on the curve, you can substitute x=0, 1, 2, 3 into the function to see what they are. For example, f(0) = 0²-3 = -3; f(1) = 1² -3 = -2; and so on. The curve is symmetrical about the y-axis, so the points on the left are mirror images of the points on the right.

Really really appreciate some help-example-1
User Abel D
by
5.4k points