Option D
There are 15 dimes and 5 nickels
Solution:
Let "d" be the number of dimes
Let "n" be the number of nickels
We know that,
Value of 1 dime = $ 0.10
Value of 1 nickel = $ 0.05
There are three times more dimes than nickels
Therefore,
Number of dimes = 3(number of nickels)
d = 3n ---------- eqn 1
The total value is $ 1.75
Therefore, we frame a equation as:
Number of dimes x Value of 1 dime + number of nickels x Value of 1 nickel = 1.75
0.10d + 0.05n = 1.75 -------- eqn 2
Substitute eqn 1 in eqn 2
0.10(3n) + 0.05n = 1.75
0.3n + 0.05n = 1.75
0.35n = 1.75
n = 5
Substitute n = 5 in eqn 1
d = 5(3)
d = 15
Thus there are 15 dimes and 5 nickels