Question

A square solar collector measures 6.00 m by 6.00 m and another solar collector measures 8.000 m by 8.000 m. using the correct number of significant figures what is the combined area of both collectors?

a) 1.00×10^2
b) 1.0 ×10^2
c)1×10^2
d) 1.000x10^2
e) 1.0000x10^2

Answer 1

The combined area of both solar collectors is 1.0 × 10² m².

Step-by-step explanation:

To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².

The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.

Answer 2

Answer:
`1.000* 10^2m^2`

Step-by-step explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least precise number present determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Area of square collector 1 =

Area of square collector 1 =
`6.00m* 6.00m=36.0m^2`

Area of square collector 2 =
`length* breadth`

Area of square collector 2 =
`8.000m* 8.000m=64.00m^2`

Combined area of both collectors = Area of square collector 1 + Area of square collector 2 =
`36.0m^2+64.00m^2=100.0m^2=1.0* 10^2m^2`

The combined area of both collectors is
`1.000* 10^2m^2`