Question

A bullet is fired through a board 13.0 cm thick in such a way that the bullet's line of motion is perpendicular to the face of the board. The initial speed of the bullet is 560 m/s and it emerges from the other side of the board with a speed of 460 m/s. (a) Find the acceleration of the bullet as it passes through the board.

Answer 1

392307.6923 m/s²

Step-by-step explanation:

t = Time taken

u = Initial velocity = 560 m/s

v = Final velocity = 460 m/s

s = Displacement = 13 cm

a = Acceleration

From the equation of motion we have

`v^2-u^2=2as\\\Rightarrow a=(v^2-u^2)/(2s)\\\Rightarrow a=(460^2-560^2)/(2* 13* 10^(-2))\\\Rightarrow a=-392307.6923\ m/s^2`

The acceleration of the bullet as it passes through the board is -392307.6923 m/s²