Answer:
New width will be
larger than old width.
Explanation:
Given width of room is
![9.3\ ft](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bmx5vgmthhvpyyxjczst5sl69loaaiaiwg.png)
And length of room is
![6.2\ ft](https://img.qammunity.org/2021/formulas/mathematics/middle-school/e4mevgcrbaj1xahdhqkc1xto456gsjp47n.png)
Then the old area will be
![(9.3* 6.2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y1rqj5nehsaio1p2xarfcvgc8o7m3h11sb.png)
Also we have to make this room three times larger as it is now.
We can see the ratio between width and length of room is
![(9.3)/(6.2)=1.5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6c9kob8p2v0rlzfgg7msq41457pv139a1a.png)
let us say the length of new room is
![x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p9sq9b3rc5nwoqzhzc8wcaj51b36281l9g.png)
So, width of room will be
![1.5* x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4j5cw7z0u7zcpvp6weeuujbxiphd5dqr96.png)
And we know area of rectangle is
![length* width](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3nlefntz988yamkp64aq5eklx732g4nfgb.png)
Also, the new area will be
![3* (9.3* 6.2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kk340cichmw1suglbjsjz8sq54y4ssy4i4.png)
Then the equation will be
![x* 1.5* x=3*(9.3* 6.2)\\1.5* x^2=172.89\\x^2=(172.89)/(1.5)\\ x^2=115.32\\x=√(115.32)\\x=10.73\ ft](https://img.qammunity.org/2021/formulas/mathematics/middle-school/siu718ed7ns30857gvpqctw3hkwya1dj8q.png)
So, the width of new room is
![1.5* x=1.5* 10.738\\width=16.107\ ft](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3tl4r8ctsjnh89m91fi1bt2fe2zk9wrjiz.png)
So, the increment in width is
![16.107-9.3=6.807\ ft](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wvsewgjd318c8rcpvdx7dtph3dtwcvv5xe.png)