Question

15 POINTS
question 11

Answer 1

Option C:

`y+6=(3)/(5) (x-4)`

Solution:

Given point (4, –6) and slope,
`m=(3)/(5)`

Formula for equation of a straight line when passing through the point
`(x_1, y_1)` and slope m is
`y-y_1=m(x-x_1)`

Here,
`x_1=4, y_1=-6, m=(3)/(5)`

Substitute these in the above formula, we get

⇒
`y-(-6)=(3)/(5) (x-4)`

⇒
`y+6=(3)/(5) (x-4)`

Hence,
`y+6=(3)/(5) (x-4)` is the equation in point-slope form.