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An astronaut standing on a platform on the Moon drops a hammer. If the hammer falls 6.0 meters vertically in 2.7 seconds, what is its acceleration?a. 1.6m/s²

b. 4.4m/s²
c. 2.2m/s²
d. 9.8m/s²

User Emptyhua
by
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1 Answer

5 votes

Option A is the correct answer.

Step-by-step explanation:

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = ?

Displacement, s = 6 m

Time, t = 2.7 s

Substituting

s = ut + 0.5 at²

6 = 0 x 2.7 + 0.5 x a x 2.7²

a = 1.65 m/s²

Acceleration is 1.65 m/s²

Option A is the correct answer.

User Yudith
by
6.7k points