Question

The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x​

Answer 1

-3,5

Explanation:

`d = \sqrt{(x _(2) - x _1) {}^(2) + (y _(2) - y _(1) {} ) {}^(2) }`

`5 = \sqrt{(x - 1) {}^(2) + ( - 1 - 2) {}^(2) }`

`5 = \sqrt{(x - 1) {}^(2) + ( - 3) {}^(2) }`

`25 = (x - 1) {}^(2) + 9`

`16 = (x - 1) {}^(2)`

`4 = x - 1`

`x = 5`

Or

`- 4 = x - 1`

`x = - 3`