Answer:
12 year old is the youngest sibling
Explanation:
Given: The ages of three siblings are all consecutive integers.
The sum of sibling´s age is 39.
Now, finding the age of youngest sibling.
Lets assume the age of youngest sibling be "x"
As given, The ages of three siblings are all consecutive integers.
∴ Age of 2nd sibling will be

Age of 3rd sibling will be

next, forming an equation for the sum of sibling´s age.
⇒

Opening the parenthesis
⇒

⇒

Subtracting both side by 3
⇒

⇒

Dividing both side by 3
⇒

∴ x= 12
Subtituting the value of x to find the age of other sibling
∴Youngest sibling age= 12 years
2nd sibling age= 13 years
3rd sibling age= 14 years
Hence, The youngest sibling is 12 years old.