Question

Round to nearest tenth and solve for x

Answer 1

`\displaystyle 9,6`

Explanation:

`\displaystyle (x)/(6,4) = csc\:42 \hookrightarrow 6,4cot\:42 = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x`

OR

`\displaystyle (6,4)/(x) = sin\:42 \hookrightarrow xsin\:42 = 6,4 \hookrightarrow (6,4)/(sin\:42) = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x`

Information on trigonometric ratios

`\displaystyle (OPPOCITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOCITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOCITE) = csc\:θ \\ (ADJACENT)/(OPPOCITE) = cot\:θ`

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