Question

The length of rectangle is eight more than twice its width. The perimeter is 96 ft. What are the dimensions

Answer 1

Because we don’t know what the width of the rectangle we make it equal to x. So to find the length you would make it 2x+8 becuase if the length is 8 more then the width you add 8 to x, x+8. And becuase the length it “twice” the with you would make it 2x+8. Now you make everything = to 96

2x+8 + 2x+8 + x + x =96 (you put each equation in twice becuase you have 2 width and length on a rectangle)
6x + 16 = 96
6x=80
X=13.3334

Now you plug in 13 in for x
2(13.333)+8=34.666( length = 34.667)

34.666+34.666+13.333+13.333=96

(Nicer numbers if you round)
35+35+13+13=96
L=35
W=13

Answer 2

L = length

W = width

L = 2(2W + 8)

W = 2W

Perimeter: 96 = 4W + 16 + 2W

96 = 6W + 16

80 = 6W

13.33 = W

Plug this into the equation:

2(13.33) + 8

26.67 + 8 or 34.67 = L