The three even integers are 66, 68 and 70
Solution:
Let the three consecutive even integers be x, x + 2, x + 4
Let the first integer be x
Let the second integer be x + 2
Let the third integer be x + 4
Given that, sum of the first and third of three consecutive integers is 136
Sum of first and third integer = 136
x + x + 4 = 136
2x + 4 = 136
2x = 136 - 4
2x = 132
x = 66
Thus the consecutive integers are:
first even integer = x = 66
second even integer = x + 2 = 66 + 2 = 68
third even integer = x + 4 = 66 + 4 = 70
Thus the three even integers are 66, 68 and 70