Question

A gram of gasoline produces 45.0 kJ of energy when burned. Gasoline has a density of 0.77 g/ml. How would you ca the amount of energy produced by burning 35. L of gasoline? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Answer 1

Step-by-step explanation:

The given data is as follows.

Density of gasoline = 0.77 g/ml

Volume of gasoline = 35 L = 35000 ml (as 1 L = 1000 ml)

As we know that density of a substance is equal to its mass divided by its volume.

Mathematically, Density =
`(mass)/(volume)`

Hence, calculate the mass of given gasoline as follows.

Density =
`(mass)/(volume)`

0.77 g/ml =
`(mass)/(35000 ml)`

mass = 26950 g

Also, it is given that 1 g of gasoline on combustion produces 45.0 kJ of energy.

Therefore, energy produced by 26950 g of combustion of gasoline will be as follows.

`45.0 * 26950`

= 1212750 kJ

Thus, we can conclude that the amount of energy produced by burning 35 L of gasoline is 1212750 kJ.