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Find the electric flux through a cylindrical Guassian surface produced by a point charge at base.

User Foosion
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Answer:

Electric flux will be
\Phi =(q)/(\epsilon _0)

Step-by-step explanation:

Let the point charge enclosed by Gaussian surface is q

We have to find the electric flux through this Gaussian surface

According to Gauss law electric flux through any closed surface is equal to
(1)/(\epsilon _0) times of charged enclosed by the surface.

So electric flux will be
\Phi =(q)/(\epsilon _0)

Gauss law is only valid for closed surface it is not applied for open surface

User Jeevanandhan
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