Question

At a certain location, Earth has a magnetic field of 0.60 â 10â4 T, pointing 75° below the horizontal in a north-south plane. A 14.6 m long straight wire carries a 11 A current

a) If the current is directed horizontally toward the east, what are the magnitude and direction of the magnetic force on the wire?
b) What are the magnitude and direction of the force if the current is directed vertically upward?

Answer 1

a)
`= 9.30* 10^(-3) N`

b)
`= 2.49* 10^(-3) N`

Step-by-step explanation:

Given data;

magnetic field
`= 0.60 * 10^(-4)  T`

current I = 11 A

length of wire L = 14.6 m

Angle
`\theta = 75 A`

a) Magnetic force due to current

`F = BIL sin \theta`

`= 0.60 * 10^(-4) * 11 * 14.6 sin 75^o`

`= 9.30* 10^(-3) N`

B) magnitude of force due upward current direction

`F = BIL sin \theta`

`= 0.60 * 10^(-4) * 11 * 14.6 sin (75^o + 90^o)`

`= 2.49* 10^(-3) N`